No. XCVI
The following diagram shows the solution of this new chess puzzle, and fulfils its conditions that no Queen should attack a Queen, no Rook a Rook, no Bishop a Bishop, and no Knight a Knight.
| B | B | B | B | Q | R | B | B |
| Kt | R | Kt | Kt | Q | |||
| Kt | R | Kt | Q | Kt | Kt | B | |
| Q | Kt | Kt | R | Kt | B | ||
| B | Kt | Kt | Q | R | |||
| B | Q | Kt | Kt | R | Kt | ||
| Kt | Kt | R | Kt | Q | Kt | ||
| R | B | Q | Kt | B | B | B | Kt |
Mr Dudeney explains that only 8 Queens or 8 Rooks can be thus placed upon the board, while the greatest number of Bishops is fourteen, and of Knights thirty-two. But as all Knights must be placed on squares of the same colour, while the Queens occupy four of each colour, and the bishops seven of each colour, it follows that only twenty-one Knights can be placed, and the arrangement shown above contains the maximum number of these pieces under the conditions.
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