CHLORINE.
In waters that have been treated with calcium hypochlorite or liquid chlorine it is frequently advisable to ascertain the presence or absence of chlorine. As the reagents which have been proposed for its detection are not specific for chlorine but give similar or identical reactions with oxidizing agents or reducible substances care must be exercised in interpreting the results of such tests: nitrites and ferric salts are of common occurrence, and chlorates also may lead to misinterpretation in waters treated with calcium hypochlorite.
Reagents.—1. Tolidin solution. One gram of o-tolidin, purified by being recrystallized from alcohol, is dissolved in 1 liter of 10 per cent hydrochloric acid.
2. Copper sulfate solution. Dissolve 1.5 grams of copper sulfate and 1 cc. of concentrated sulfuric acid in distilled water and dilute the solution to 100 cc.
3. Potassium bichromate solution. Dissolve 0.025 gram of potassium bichromate and 0.1 cc. of concentrated sulfuric acid in distilled water and dilute the solution to 100 cc.
Procedure.—Mix 1 cc. of the tolidin reagent with 100 cc. of the sample in a Nessler tube and allow the solution to stand at least 5 minutes. Small amounts of free chlorine give a yellow and larger amounts an orange color.
For quantitative determination compare the color with that of standards in similar tubes prepared from the solutions of copper sulfate and potassium bichromate. The amounts of solution for various standards are indicated in Table 13.
| Table 13.—Preparation of permanent standards for content of chlorine. | ||
|---|---|---|
| Chlorine. | Solution of copper sulfate. | Solution of potassium bichromate. |
| Parts per million. | cc. | cc. |
| 0.01 | 0.0 | 0.8 |
| .02 | .0 | 2.1 |
| .03 | .0 | 3.2 |
| .04 | .0 | 4.3 |
| .05 | .4 | 5.5 |
| .06 | .8 | 6.6 |
| .07 | 1.2 | 7.5 |
| .08 | 1.5 | 8.7 |
| .09 | 1.7 | 9.0 |
| .10 | 1.8 | 10.0 |
| .20 | 1.9 | 20.0 |
| .30 | 1.9 | 30.0 |
| .40 | 2.0 | 38.0 |
| .50 | 2.0 | 45.0 |
DISSOLVED OXYGEN.[[16]][[65]][[68]][[71b]][[99]][[100c]][[120]]
Reagents.—1. Sulfuric acid, concentrated. (Sp. gr. 1.83–1.84.)
2. Potassium permanganate. Dissolve 6.32 grams of the salt in water and dilute the solution to 1 liter.
3. Potassium oxalate. A 2 per cent solution.
4. Manganous sulfate. Dissolve 480 grams of the salt in water and dilute the solution to 1 liter.
5. Alkaline potassium iodide. Dissolve 700 grams of potassium hydroxide and 150 grams of potassium iodide in water and dilute the solution to 1 liter.
6. Hydrochloric acid. Concentrated (Sp. gr. 1.18–1.19).
7. Sodium thiosulfate. A N/40 solution. Dissolve 6.2 grams of chemically pure recrystallized sodium thiosulfate in water and dilute the solution to 1 liter with freshly boiled distilled water. Each cc. is equivalent to 0.2 mg. of oxygen or to 0.1395 cc. of oxygen at 0°C. and 760 mm. pressure. Inasmuch as this solution is not permanent it should be standardized occasionally against a N/40 solution of potassium bichromate. The keeping qualities of the thiosulfate solution are improved by adding to each liter 5 cc. of chloroform and 1.5 grams of ammonium carbonate before diluting to the prescribed volume.
8. Starch solution. Mix a small amount of clean starch with cold water until it becomes a thin paste and stir this mass into 150 to 200 times its weight of boiling water. Boil for a few minutes, then sterilize. It may be preserved by adding a few drops of chloroform.
Collection of sample.—Collect the sample in a narrow-necked glass-stoppered bottle of 250 to 270 cc. capacity. The following procedure should be followed in order to avoid entrainment or absorption of atmospheric oxygen. In collecting from a tap fill the bottle through a glass or rubber tube extending well into the tap and to the bottom of the bottle. To avoid air bubbles allow the bottle to overflow for several minutes, and then carefully replace the glass stopper so that no air bubble is entrained. In collecting from the surface of a pond or tank connect the sample bottle to a bottle of 1 liter capacity. Provide each bottle with a two-hole rubber stopper having one glass tube extending to the bottom and another glass tube entering but not projecting into the bottle. Connect the short tube of the sample bottle with the long tube of the liter bottle. Immerse the sample bottle in the water and apply suction to the outlet of the liter bottle. To collect a sample at any depth arrange the two bottles so that the outlet tube of the liter bottle is at a higher elevation then the inlet tube of the sample bottle. Lower the two bottles, in any convenient form of cage properly weighted, to the desired depth. Water entering during the descent will be flushed through into the liter bottle. When air bubbles cease rising to the surface raise the bottles. Finally replace the perforated stopper of the sample bottle with a glass stopper in such manner as to avoid entraining bubbles of air.
Procedure.—Remove the stopper from the bottle and add, first, 0.7 cc. of the concentrated sulfuric acid, and then 1 cc. of the potassium permanganate solution. These and all other reagents should be introduced by pipette under the surface of the liquid. Insert the stopper and mix by inverting the bottle several times. After 20 minutes have elapsed destroy the excess of permanganate by adding 1 cc. of the potassium oxalate solution, the bottle being at once restoppered and its contents mixed. If a noticeable excess of potassium permanganate is not present at the end of 20 minutes, again add 1 cc. of the potassium permanganate solution. If this is still insufficient use a stronger potassium permanganate solution. After the liquid has been decolorized by the addition of potassium oxalate add 1 cc. of the manganous sulfate solution and 3 cc. of the alkaline potassium iodide solution. Allow the precipitate to settle. Add 2 cc. of the hydrochloric acid and mix by shaking.
The procedure to this point must be carried out in the field, but after the acid has been added and the stopper replaced there is no further change, and the rest of the test may be performed within a few hours, as convenient. Transfer 200 cc. of the contents of the bottle to a flask and titrate with N/40 sodium thiosulfate, using a few cubic centimeters of the starch solution as indicator toward the end of the titration. Do not add the starch solution until the color has become faint yellow, and titrate until the blue color disappears.
The use of potassium permanganate is made necessary by high nitrite or organic matter. The procedure outlined must be followed in all work on sewage and partly purified effluents or seriously polluted streams or samples whose nitrite nitrogen exceeds 0.1 part per million. In testing other samples the procedure may be shortened by beginning with the addition of the manganous sulfate solution and proceeding from that point as outlined, except that only 1 cc. of alkaline potassium iodide need be added.
Calculation of Results.—Oxygen shall be reported in parts per million by weight. It is sometimes convenient to know the number of cubic centimeters per liter of the gas at 0°C. temperature and 760 mm. pressure and also to know the percentage which the amount of gas present is of the maximum amount capable of being dissolved by distilled water at the same temperature and pressure. If 200 cc. of the sample is taken the number of cubic centimeters of N/40 thiosulfate used is equal to parts per million of oxygen. Corrections for volume of reagents added amount to less than 3 per cent and are not justified except in work of unusual precision. To obtain the result in cubic centimeters per liter multiply the number of cubic centimeters of thiosulfate used by 0.698. To obtain the result in percentage of saturation divide the number of cubic centimeters of thiosulfate by the figure in Table 14 opposite the temperature of the water and under the proper chlorine figure. The last column of Table 14 permits interpolation for intermediate chlorine values. At elevations differing considerably from mean sea level and for accurate work attention must be given to barometric pressure, the normal pressure in the region being preferable to the specific pressure at the time of sampling. The term “saturation” refers to a condition of equilibrium between the solution and an oxygen pressure in the atmosphere corresponding to 158.8 millimeters, or approximately one-fifth atmosphere. The true saturation or equilibrium between the solution and pure oxygen is nearly five times this value, and consequently values in excess of 100 per cent saturation frequently occur in the presence of oxygen-forming plants.
| Table 14.—Solubility of oxygen in fresh water and in sea water of stated degrees of salinity at various temperatures when exposed to an atmosphere containing 20.9 per cent of oxygen under a pressure of 760 mm.[[F]] | ||||||
|---|---|---|---|---|---|---|
| (Calculated by G. C. Whipple and M. C. Whipple from measurements of C. J. Fox.)[[27]][[119]] | ||||||
| Temperature. | Chloride in sea water (milligrams per liter). | Difference per 100 parts of chloride. | ||||
| 0. | 5000. | 10000. | 15000. | 20000. | ||
| °C. | Dissolved oxygen in milligrams per liter. | Parts per million. | ||||
| 0 | 14.62 | 13.79 | 12.97 | 12.14 | 11.32 | 0.0165 |
| 1 | 14.23 | 13.41 | 12.61 | 11.82 | 11.03 | .0160 |
| 2 | 13.84 | 13.05 | 12.28 | 11.52 | 10.76 | .0154 |
| 3 | 13.48 | 12.72 | 11.98 | 11.24 | 10.50 | .0149 |
| 4 | 13.13 | 12.41 | 11.69 | 10.97 | 10.25 | .0144 |
| 5 | 12.80 | 12.09 | 11.39 | 10.70 | 10.01 | .0140 |
| 6 | 12.48 | 11.79 | 11.12 | 10.45 | 9.78 | .0135 |
| 7 | 12.17 | 11.51 | 10.85 | 10.21 | 9.57 | .0130 |
| 8 | 11.87 | 11.24 | 10.61 | 9.98 | 9.36 | .0125 |
| 9 | 11.59 | 10.97 | 10.36 | 9.76 | 9.17 | .0121 |
| 10 | 11.33 | 10.73 | 10.13 | 9.55 | 8.98 | .0118 |
| 11 | 11.08 | 10.49 | 9.92 | 9.35 | 8.80 | .0114 |
| 12 | 10.83 | 10.28 | 9.72 | 9.17 | 8.62 | .0110 |
| 13 | 10.60 | 10.05 | 9.52 | 8.98 | 8.46 | .0107 |
| 14 | 10.37 | 9.85 | 9.32 | 8.80 | 8.30 | .0104 |
| 15 | 10.15 | 9.65 | 9.14 | 8.63 | 8.14 | .0100 |
| 16 | 9.95 | 9.46 | 8.96 | 8.47 | 7.99 | .0098 |
| 17 | 9.74 | 9.26 | 8.78 | 8.30 | 7.84 | .0095 |
| 18 | 9.54 | 9.07 | 8.62 | 8.15 | 7.70 | .0092 |
| 19 | 9.35 | 8.89 | 8.45 | 8.00 | 7.56 | .0089 |
| 20 | 9.17 | 8.73 | 8.30 | 7.86 | 7.42 | .0088 |
| 21 | 8.99 | 8.57 | 8.14 | 7.71 | 7.28 | .0086 |
| 22 | 8.83 | 8.42 | 7.99 | 7.57 | 7.14 | .0085 |
| 23 | 8.68 | 8.27 | 7.85 | 7.43 | 7.00 | .0083 |
| 24 | 8.53 | 8.12 | 7.71 | 7.30 | 6.87 | .0083 |
| 25 | 8.38 | 7.96 | 7.56 | 7.15 | 6.74 | .0082 |
| 26 | 8.22 | 7.81 | 7.42 | 7.02 | 6.61 | .0080 |
| 27 | 8.07 | 7.67 | 7.28 | 6.88 | 6.49 | .0079 |
| 28 | 7.92 | 7.53 | 7.14 | 6.75 | 6.37 | .0078 |
| 29 | 7.77 | 7.39 | 7.00 | 6.62 | 6.25 | .0076 |
| 30 | 7.63 | 7.25 | 6.86 | 6.49 | 6.13 | .0075 |
[F]. Under any other barometric pressure, B, the solubility can be obtained from the corresponding value in the table by the formula:
| S´ = SB 760 = SB´ 29.92 in which | S´ = Solubility at B or B´, |
| S = Solubility at 760 mm. or 29.92 inches, | |
| B = Barometric pressure in mm., | |
| and | B´ = Barometric pressure in inches. |
ETHER-SOLUBLE MATTER.[[44]]
Evaporate 500 cc. of the sample in a porcelain evaporating dish to a volume of about 50 cc. By means of a rubber-tipped glass rod remove to the bottom of the dish the solid matter attached to the sides, and add normal sulfuric acid to neutralize the alkalinity. Do not use an excess of acid. Then evaporate the contents of the dish to dryness. Treat the dry residue with boiling ether, rubbing the bottom and sides of the dish to insure complete solution of fat. Three extractions with ether are required. Filter the ether solution through a 5 cm. filter into a weighed flask having a wide mouth. Evaporate the ether slowly, and dry the flask at 100° C. for 30 minutes. The increase in weight of the flask gives the amount of fats, or, in more precise language, the ether-soluble matter.
An excess of acid gives too high results because of the formation of fatty-acid residues.
RELATIVE STABILITY OF EFFLUENTS.[[78]]
Reagent.—Methylene blue solution. A 0.05 per cent aqueous solution of methylene blue, preferably the double zinc salt or commercial variety.[[60b]]
Collection of sample.—Collect the sample in a glass-stoppered bottle holding approximately 150 cc. If the dissolved oxygen is low observe precautions similar to those used in collecting samples for dissolved oxygen (p. [66]).
Procedure.—Add 0.4 cc. of the methylene blue solution to the sample in the 150 cc. bottle. As methylene blue has a slightly antiseptic property be careful to add exactly 0.4 cc. Add the methylene blue solution preferably below the surface of the liquid after filling the bottle with the sample. If the methylene blue is added first do not allow the liquid to overflow as coloring matter will thus be lost. Incubate the sample at 20° C. for ten days. Four days’ incubation may be considered sufficient for all practical purposes in routine plant-control work. If quick results are desired incubate the sample at 37° C. for five days using suitable stoppers[[1a]][[2a]] to prevent the loss and reabsorption of dissolved oxygen. The bacterial flora at 37° C. is different from that at 20° C. The lower temperature is more nearly the average temperature of surface waters and therefore the higher temperature should be used only when quick approximate results are essential. Observe the sample at least twice a day during incubation. Give a sample in which the methylene blue becomes decolorized a relative stability corresponding to the time required for reduction (see Table 15). For routine filter control ordinary room or cellar temperature gives fairly satisfactory results. For accurate studies, room temperature incubation is very undesirable, as the fluctuations in temperature which are ordinarily not noticed are responsible for appreciable deviations from the true values of relative stability. If the samples are incubated less than 10 days at 20° C. and are not decolorized place a plus sign after the stability value in order to indicate that the stability might have been higher if more time had been allowed. In applying this test to river waters it often happens that the blue coloring matter is removed either partly or completely through absorption by the clay which many rivers carry in suspension. True relative stabilities cannot be obtained for such waters except by determining the initial available oxygen at the start and the biochemical oxygen demand on incubation at 20° C. for 10 days (pp. [71]–73). Germicides, such as hypochlorite of lime, if present in sufficient quantity, vitiate the results. If a sample contains free chlorine, therefore, store it about 2 hours, or until the chlorine is gone, and then add methylene blue.
Table 15[[78]] gives the relation between the time in days to decolorize methylene blue at 20° C. (t20) and the relative stability number or ratio of available oxygen to oxygen required for equilibrium, expressed in percentage (S).
| Table 15.—Relative stability numbers. | |
| Time required for decolorization at 20° C. | Relative stability. |
|---|---|
| Days. | Percentage. |
| 0.5 | 11 |
| 1.0 | 21 |
| 1.5 | 30 |
| 2.0 | 37 |
| 2.5 | 44 |
| 3.0 | 50 |
| 4.0 | 60 |
| 5.0 | 68 |
| 6.0 | 75 |
| 7.0 | 80 |
| 8.0 | 84 |
| 9.0 | 87 |
| 10.0 | 90 |
| 11.0 | 92 |
| 12.0 | 94 |
| 13.0 | 95 |
| 14.0 | 96 |
| 16.0 | 97 |
| 18.0 | 98 |
| 20.0 | 99 |
The theoretical relation is, S = 100 (1 − 0.794t20)
The relation between the time of reduction at 20° C. and that at 37° C. is approximately two to one, but if an observer incubates at 37° C. he should work out his own comparative 37° C. table or factor.
A relative stability of 75 signifies that the sample examined contains a supply of available oxygen equal to 75 per cent of the amount of oxygen which it requires in order to become perfectly stable. The available oxygen is approximately equivalent to the dissolved oxygen plus the available oxygen of nitrate and nitrite. Nitrite in sewage is usually so low as to be negligible.
BIOCHEMICAL OXYGEN DEMAND OF SEWAGE AND EFFLUENTS.[[60a]][[60c]][[60d]]
RELATIVE STABILITY METHOD.
The relative stability method may be employed to obtain a measure of the putrescible material in sewages and effluents in terms of oxygen demand.
Procedure for effluents.—Divide the total available oxygen, including the oxygen of nitrite and nitrate, by the relative stability expressed as a decimal.
Procedure for sewages.—Make one or two dilutions with fully aerated distilled water of known dissolved oxygen content. Tap water may be employed if it is free from nitrates. Vary the relative proportions of sewage and water to be employed to give a relative stability of 50 to 75. Unless seals[[1b]][[2b]][[52a]] are used bring the water as well as the sewage to the temperature at which the mixtures are to be incubated before preparing the dilutions. During the manipulation avoid aeration. Having made the proper dilutions, determine the relative stability of each.
Calculate the oxygen demand in parts per million by the formula:
Oxygen demand = O(1 − p)/Rp
In this formula, O is the initial dissolved oxygen of the diluting water, p is the proportion of sewage; and R is the relative stability of the mixture. Ordinarily the available oxygen in crude sewages, septic tank effluents, settling tank effluents, and trade wastes can be neglected.
SODIUM NITRATE METHOD.
For the determination of the biochemical oxygen demand the sodium nitrate method may be used[[60a]][[60c]][[60d]][[52a]]. The method is based on the biochemical consumption of oxygen from sodium nitrate by a sewage or polluted water during an incubation period of ten days at 20° C. A reasonable excess of sodium nitrate does not give a higher oxygen demand, as do higher dilutions with aerated water. The oxygen absorbed from the air in applying the method to sewages is negligible.
Reagent.—Sodium nitrate solution. Dissolve 26.56 grams of pure sodium nitrate in 1 liter of distilled water. One cc. of this solution in 250 cc. of sewage represents 50 parts per million of available oxygen. The strength of the sodium nitrate solution may be varied to suit conditions.
Procedure for sewages.—Ordinarily disregard the initial available oxygen as it is very small compared with the total biochemical oxygen demand. Add measured amounts of the sodium nitrate solution to the sewage in bottles holding approximately 250 cc. which have been completely filled and stoppered. Incubate for 10 days at 20° C. A seal is not required during incubation. The appearance of a black sediment and the development of a putrid odor during incubation indicates that too little sodium nitrate has been added. Methylene blue solution in proper proportion may be added at the start to serve as an indicator during the incubation. Domestic sewage usually varies in its oxygen demand from 100 to 300 parts per million, approximately 30 per cent of which is used up at 20° C. in the first 24 hours. At the end of the incubation period determine the residual nitrite and nitrate. Determine the nitrate by the aluminium reduction method and direct Nesslerization. To convert the nitrogen into oxygen equivalents, multiply the nitrite nitrogen by 1.7 and the nitrate nitrogen by 2.9. The difference between the available oxygen added as sodium nitrate and that found as nitrite and nitrate at the end of the incubation period is the biochemical oxygen demand.
Procedure for industrial wastes.—Employ the same procedure using larger quantities of the sodium nitrate solution. Make the reaction alkaline to methyl orange and acid to phenolphthalein. Adjust an acid reaction with sodium bicarbonate and a caustic alkaline reaction with weak hydrochloric acid. If the liquid is devoid of sewage bacteria seed it with sewage after adjusting the reaction.
Procedure for polluted river waters.—Determine the initial available oxygen. Unless the river water is badly polluted add 10 parts per million of sodium nitrate oxygen. Collect carefully, avoiding aeration, three samples in 250 cc. bottles. To one sample add a definite quantity of sodium nitrate solution and incubate. Incubate the other two samples for the determination of the residual free oxygen, nitrite, and nitrate. If there is free oxygen left, the bottle containing the sodium nitrate solution may be discarded. If there is no free oxygen determine residual nitrite and nitrate as directed under the procedure for sewage (p. [72]) and calculate the oxygen demand.