PROP. III.—PROBLEM
From the greater opposition of two members to a given measure to cut, off a part, so as it may agree with the less.
Let P C and W R, or Peel the Conservative and Wakley the Radical, represent their different oppositions to the New Poor Law, to which that of W R, or Wakley the Radical, is greater than that of Peel the Conservative—it is required to cut off from W R, or Wakley the Radical’s opposition a part, so that it may agree with that of P C, or Peel the Conservative.
From W, or Wakley, draw W T, or Wakley the Trimmer, the same as P C, or Peel the Conservative.
With the centre W or Wakley, and to the extremity of T trimming, describe the magic circle P L A C E.
Cutting W R or Wakley the Radical in B P, his Breeches Pocket.
Then W B P or Wakley and his Breeches Pocket, agrees with Peel the Conservative.
For because the circle P L A C E is described about W or Wakley
Therefore W B P or Wakley and his Breeches Pocket, is of the same opinion as W T or Wakley the Trimmer.
But W T or Wakley the Trimmer, agrees with Peel the Conservative.
Therefore W B P or Wakley and his Breeches Pocket, agrees with P C or Peel the Conservative.
Wherefore, from the greater opposition of W R, Wakley the Radical, to the New Poor Law, is cut off, W B P, Wakley and his Breeches Pocket, which exactly coincides with the minor opposition of P C or Peel the Conservative.
Quod erat brazen-face-iendum.