ψ(2) = A₂ φ(2) = x₂
ψ(3) = A₃ φ(3) = x₃
ψ(4) = A₄ φ(4) = x₄.
in order to arrive at the result that Sμ is equal to Aμ.
In order to prove then that Aμν is a tensor when on the right side of (26) we substitute any co-variant four-vector for Aμ we have only to show that this is true for the four-vector Sμ. For this latter case, however, a glance on the right hand side of (26) will show that we have only to bring forth the proof for the case when
Aμ = ψ ∂φ/∂xμ.
Now the right hand side of (25) multiplied by ψ is
which has a tensor character. Similarly, (∂φ/∂xμ) (∂φ/∂xν) is also a tensor (outer product of two four-vectors).
Through addition follows the tensor character of