(52a) ∂/∂xα(gσβ Γμβα - ½ δμσ gλβ Γλβα)

= -κ(tμσ + Tμσ)

we operate on it by ∂/∂xσ. Now,

∂²/∂xαxσ (gσβΓμβα)

= -½ ∂²/∂xαxσ [gσβ gαλ(∂gμλ/∂xβ

+ ∂gβλ/∂xμ - ∂gμβ/∂xλ)].

The first and the third member of the round bracket lead to expressions which cancel one another, as can be easily seen by interchanging the summation-indices α, and σ, on the one hand, and β and λ, on the other.

The second term can be transformed according to (31). So that we get,

(54) ∂²/∂xαxσ (gσβγμβα)

= ½ ∂³gαβ/∂xσxβxμ