and multiplying (2·1) by i we get
∂iex/∂x₁ + ∂iey/∂x₂ + ∂iez/∂x₃ = iρ = ρ₄ ... ... (2·2)
Now substitute
mx = f₂₃ = -f₃₂ and iex = f₄₁ = -f₁₄
my = f₃₁ = -f₁₃ iey = f₄₂ = -f₂₄
mz = f₁₂ = -f₂₁ iez = f₄₃ = -f₃₄
and we get finally:—
∂f₁₂/∂x₂ + ∂f₁₃/∂x₃ + ∂f₁₄/∂x₄ = ρ₁ }
∂f₂₁/∂x₁ + ∂f₂₃/∂x₃ + ∂f₂₄/∂x₄ = ρ₂ } ... (3)
∂f₃₁/∂x₁ + ∂f₃₂/∂x₂ + ∂f₃₄/∂x₄ = ρ₃ }