Bx = (Bx x, Bx y, Bx z) }
By = (By x, By y, By z) } (Bi k = - Bk i, Bi i = 0).
Bz = (Bz x, Bz y, Bz z) }
Since Bj j is zero, Bj is perpendicular to the j-axis. The j-component of the vector-product of A and B is equivalent to the scalar product of A and Bj, i.e.,
(A Bj,) = Ax Bj x + Ay Bj y + Az Bj z.
We see easily that this coincides with the usual rule for the vector-product; e. g., for j = x.
(ABx) = Ay Bx y - Az Bz x.
Correspondingly let us define in the four-dimensional case the product (Pf) of any four-vector P and the six-vector f. The j-component (j = x, y, z, or l) is given by
(Pfj) = Pxfj x + Pyfj y + Pwfj z + Pzfj l
Each one of these components is obtained as the scalar product of P, and the vector fj which is perpendicular to j-axis, and is obtained from f by the rule fj = [(fj x, fj y, fj z, fj l) fj j = 0.]