(1) It will evolve SH2 when treated with HCl, and at the same time pass into solution.[818]
[818] By adding chloride of tin to a solution of chloride of antimony in sufficient quantity, and passing SO2 through the liquid, the whole of the antimony can be thrown down as sulphide, whilst the tin remains in solution. Thus,—
9SnCl2 + 2SbCl3 + 3SO2 + 12ClH = Sb2S3 + 9SnCl4 + 6OH2.
—Federow, Zeitschrift für Chemie, 1869, p. 16.
(2) The solution evaporated to get rid of free HCl gives with water a thick cheesy precipitate of basic chloride of antimony. This may be seen if only a drop or two of the solution be taken and tested in a watch-glass.
(3) If tartaric acid be added to the solution, this precipitation does not occur.
(4) The solution from (3) gives an orange precipitate with SH2.