the result is the day of April, on which Easter Sunday falls. (39; Easter Day is April 8).
In the following examples, the several results leading to the final conclusion are tabulated.
| Given Year | 1592 | 1637 | 1723 | 1853 | 2018 | 4686 |
| I. | 1593 | 1638 | 1724 | 1854 | 2019 | 4687 |
| II. | 398 | 409 | 430 | 463 | 504 | 1171 |
| III. | — | 0 | 1 | 2 | 4 | 30 |
| IV. | — | 0 | 0 | 0 | 1 | 7 |
| V. | 1991 | 2047 | 2153 | 2315 | 2520 | 5835 |
| VI. | 3 | 3 | 4 | 5 | 0 | 4 |
| VII. | 4 | 4 | 3 | 2 | 7 | 3 |
| VIII. | 16 | 4 | 14 | 11 | 5 | 13 |
| IX. | — | — | 0 | 0 | 0 | 1 |
| X. | 0 | 0 | 0 | 1 | 1 | 10 |
| XI. | 16 | 4 | 24 | 21 | 15 | 13 |
| XII. | 16 | 4 | 23 | 20 | 13 | 0 say 30 |
| XIII. | 29 | 41 | 22 | 25 | 32 | 45 |
| XIV. | 4 | 2 | 4 | 7 | 7 | 6 |
| XV. | 29 | 43 | 28 | 27 | 32 | 49 |
| Easter Day | Mar.29 | Apr.12 | Mar.28 | Mar.27 | Apr.1 | Apr.18 |
13. Rule for determining Easter Day of the Antegregorian Calendar in any year of the old style. To the several parts of the rule are annexed, by way of example, the results for the year 1287. The steps are numbered to correspond with the steps of the Gregorian rule, so that it can be seen what augmentations the latter requires.
I. Set down the given year. (1287).
II. Take the quotient of the given year divided by 4, neglecting the remainder (321).
V. Take 4 more than the sum of I. and II. (1612).
VI. Find the remainder of V. divided by 7. (2).
VII. Subtract VI. from 7; this is the number of the dominical letter
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | (5; dominical letter E). |
| A | B | C | D | E | F | G |