- £ s. d. £ s. d.
- 13)99 15 9¼(7 13 6¼
- 91
- 8
- 20
- 160 + 15 = 175
- 13
- 45
- 39
- 6
- 12
- 72 + 9 = 81
- 78
- 3
- 4
- 12 + 1 = 13
- 13
- 0
Here, each of the numbers 99, 175, 81, and 13, is divided by 13 in the usual way, though the divisor is only written before the first of them.
EXERCISES.
| 2 cwt. 1 qr. 21 lbs. 7 oz. × 53 | = | 129 cwt. 1 qr. 16 lbs. 3 oz. |
| 2ᵈ 4ʰ 3ᵐ 27ˢ × 109 | = | 236ᵈ 10ʰ 16ᵐ 3ˢ |
| £27 . 10 . 8 × 569 | = | £15666 . 9 . 4 |
| £7 . 4 . 8 × 123 | = | £889 . 14 |
| £166 × ₈/₃₃ | = | £40 . 4 . 10⁶/₃₃ |
| £187 . 6 . 7 × ³/₁₀₀ | = | £5 . 12 . 4¾ ²/₂₅ |
| 4s. 6½d. × 1121 | = | £254 . 11 . 2½ |
| 4s. 4d. × 4260 | = | 6s. 6d. × 2840 |
229. Suppose it required to find how many times 1s. 4¼d. is contained in £3. 19. 10¾. The way to do this is to find the number of farthings in each. By 219, in the first there are 65, and in the second 3835 farthings. Now, 3835 contains 65 59 times; and therefore the second quantity is 59 times as great as the first. In the case, however, of pounds, shillings, and pence, it would be best to use decimals of a pound, which will give a sufficiently exact answer. Thus 1s. 4¼d. is £·067, and £3. 19. 10¾ is £3·994, and 3·994 divided by ·067 is 3994 by 67, or 59⁴¹/₆₇. This is an extreme case, for the smaller the divisor, the greater the effect of an error in a given place of decimals.
EXERCISES.
How many times does 6 cwt. 2 qrs. contain 1 qr. 14 lbs. 1 oz.? and 1ᵈ 2ʰ 0ᵐ 47ˢ contain 3ᵐ 46ˢ?
Answer, 17·30758 and 414·367257.
If 2 cwt. 3 qrs. 1 lb. cost £150. 13. 10, how much does 1 lb. cost?
Answer, 9s. 9d. ¹³/₃₀₉.