Remark.—It is now clear that Y led from five hearts originally (see his lead, Trick 3, and p. [116]). Consequently, YZ have all the remaining hearts between them.
Trick 10.
Tricks AB, 3
YZ, 7
10. A Y B Z↷
9♦ 7♣ 2♦ 6♦
Remark.—Z can count his partner's hand, viz., three more hearts (see Remark, Trick 9) and one other card, either the deuce of diamonds (see the fall of the diamonds, Tricks 4 and 5), or a trump. If Y has the diamond, it matters not what Z leads, as B must then hold four trumps. Z therefore assumes that his partner has another trump, and plays to force him.
But if Z could not tell that Y has three hearts, or rather could tell that he has only two, Z's proper lead at Trick 10 would be the ace of hearts. For then B must have a heart, and if Z leads a losing diamond, B discards his heart on it, and wins the game.
THE HANDS.
(Z's hand is given above.)
| A's Hand. | Y's Hand. | B's Hand. | |||
| Kg, Knv, 8, 4, 3, 2 | ♠ | Ace, 5 | ♠ | 9, 7, 6 | ♠ |
| Knv | ♥ | Kg, 10, 9, 7, 2 | ♥ | 8, 3 | ♥ |
| Ace, Kg | ♣ | 7, 6, 4, 3 | ♣ | Qn, Knv, 10, 5, 2 | ♣ |
| Qn, 9, 8, 7 | ♦ | Ace, 10 | ♦ | Kg, 4, 2 | ♦ |
At Trick 6, B should play to force his partner in hearts instead of leading trumps.