Trick 9.
Tricks AB, 5
YZ, 4
9. B↷ Z A Y
10♥ 10♠ 8♣ 5♥
Trick 10.
Tricks AB, 6
YZ, 4
10. B Z↷ A Y
Knv♣ 8♦ 2♠ 6♥
Remark (Trick 10).—Y's play in not overtrumping is very good. He counts the hand thus: to save the game Z must hold ace, queen, or ace, knave of spades; his third card is evidently the remaining diamond. A has the nine of clubs (see fall of the club suit in Tricks 2, 7, and 9), and two trumps. B has two trumps, one being queen or knave (see Trick 9), and king, knave of clubs. If the cards remaining in each hand are placed face upwards on the table, and the uncertain cards, viz., the nine, four, and three of trumps are given two to A, and one to B, it will be seen that, if Y overtrumps with the seven, he cannot make the requisite three tricks; but that, if he leaves the lead with A, YZ make the remaining tricks.
It may be added, that if, at Trick 10, A discards his club, and keeps his three little trumps together, leaving the trick to B, AB must win the odd trick if B leads a trump at Trick 11 after trumping. This A might have reckoned.