.4771 + 1.0453x = 1.2430x
.198x = .4771
x = 2.41
solving for the constant K
5 = K 11.12.41
5 = 332 K
K = .0150
and the final equation for the candle power is
cp = .0150 × w2.41
In the same way, the candle power may be expressed in terms of the voltage and this is found to be