Then, if the situations a b, a g, a l, a q, a v, and a B are responded to, each once, we have:—
| a + b | responded to by | r1 + r2, | |
| a + g | " " | r1 + rnot 2, | |
| a + l | " " | r1 + r12, | |
| a + q | " " | r1 + rnot 12, | |
| a + v | " " | r1 + r22, and | |
| a + B | " " | r1 + rnot 22, as shown in Scheme II. |
Scheme II
| a | b | g | l | q | v | B | |
| (opp. of b) | (opp. of l) | (opp. of v) | |||||
| r1 | 6 | 1 | 1 | 1 | 1 | 1 | 1 |
| rnot 1 | |||||||
| r2 | 1 | 1 | |||||
| rnot 2 | 1 | 1 | |||||
| r12 | 1 | 1 | |||||
| rnot 12 | 1 | 1 | |||||
| r22 | 1 | 1 | |||||
| rnot 22 | 1 | 1 |
r1 is connected to a by 6 repetitions. r2 and rnot 2 are each connected to a by 1 repetition, but since they interfere, canceling each other so to speak, the net result is for a to have zero tendency to call up r2 or rnot 2. r12 and rnot 12 are each connected to a by 1 repetition, but they interfere with or cancel each other with the net result that a has zero tendency to call up r12 or rnot 12. So with r22 and rnot 22. Here then the net result of the six connections of a b, a g, a l, a q, a v, and a B is to connect a with r, and with nothing else.
Case III. Contrasting Concomitants and Contrasting Element
Suppose now that the facts are as in Case II, but with the addition of six experiences where a certain element which is the opposite of, or very dissimilar to, a is connected with the response rnot 1, or r-1 which is opposite to, or very dissimilar to r1. Call this opposite of a, − a.
That is, we have not only
| a + b | responded to by | r1 + r2, | |
| a + g | " " | r1 + rnot 2, | |
| a + l | " " | r1 + r12, | |
| a + q | " " | r1 + rnot 12, | |
| a + v | " " | r1 + r22, and | |
| a + B | " " | r1 + rnot 22, |
but also