E₀ + E1
x2 = ---------- KT
d
Suppose that the positive carriers are produced at a uniform rate of q per second for unit distance between the plates. The number of positive carriers which reach B during a half alternation consists of two parts:
(1) One half of those carriers which are produced within the distance x1 of the plate B. This number is equal to
1
--- x1 qT
2
(2) All the carriers which are left within the distance x1 from B at the end of the previous half alternation. The number of these can readily be shown to be
1 x1