dQ/dt = λ1P – λ2Q (1).
Similarly dR/dt = λ2Q – λ3R (2).
Substituting in (1) the value of P in terms of n,
The solution of this equation is of the form
By substitution it is found that a = λ1/(λ2 – λ1).
Since Q = 0 when t = 0, b = -λ1(λ2 – λ1).
Thus
dQ/dt = λ1P – λ2Q (1).
Similarly dR/dt = λ2Q – λ3R (2).
Substituting in (1) the value of P in terms of n,
The solution of this equation is of the form
By substitution it is found that a = λ1/(λ2 – λ1).
Since Q = 0 when t = 0, b = -λ1(λ2 – λ1).
Thus