There are eight hieroglyphs above this picture, just as there are over each of the first four serpents. The two top hieroglyphs are obliterated. Of the legible hieroglyphs, the one at the left top is the Bacab sign, which also occurs over the first of the four serpents. In the third line are the same two hieroglyphs, which are in the third line of the first and second columns on page 70. The first of the two also occupies the same place on page 62 above the fourth serpent. But here at the bottom we find the date IX Kan 12 Kayab (4 Ix), the same date which we found over the fourth serpent, which is thus again brought into closer connection with the single serpent.
There can be no doubt here regarding the two numbers in the serpents, but notice should be taken of the fact that the figure 1 is barely visible in the red number.
The black number here has the figures 4. 5. 19. 13. 12. 8. and the red 4. 6. 1. 0. 13. 10. The black is therefore 12,381,728, and the red 12,391,470. The black number is somewhat less than the eight numbers in the four serpents, and the red is somewhat larger than the least of them.
The difference of the two is 9742 = 37 × 260 + 122; but 122 is the interval between days IV Eb and IX Ix. Now this is the same 9742 which we found on page 70, as the difference between 111,554 and 101,812.
In order not merely to examine these numbers, but also to understand them, we will again make use of 109 Ahau-Katuns = 12,412,920, as we did in the first four serpents, and we shall have the following:—
| Black | Red | ||
| 12,381,728 | 12,391,470 | ||
| 12,412,920 | 12,412,920 | ||
| ————— | ————— | ||
| -31,192 | = 119 × 260 + 252 | -21,450 | = 82 × 260 + 130 |
| IV Eb - IX Kan = 252 | IX Ix - IX Kan = 130 | ||
The date given for both numbers was the day IX Kan, which was likewise the starting-point for six of the eight numbers in the previous serpents.
Besides this the day IV Eb, the starting-point of the 65-series, is given for the black number, and therefore also the interval between IV Eb and IX Kan = 252.
To this 252 was added a multiple of 260, not an arbitrary choice, but one which combined with 252 resulted in a number divisible by 8, the interval from IX Kan to IV Eb. 31,192 = 3899 × 8 = 119 × 260 + 252 was thus obtained.