1) 1,352,400 = 28 × 48,300 and = 115 × 11,760, hence it is divisible by the month days of the year of 364 days and by the Mercury year. At all events this is the least important of the three numbers.
2) 1,364,360. This looks as if it referred particularly to the moon and to Mercury; to the latter since it is equal to 115 × 11,864, and to the former if we assume that the lunar revolution has been fixed at 29⅔ days, in which case this number is exactly equal to 46,000 such lunations. If this last number be again divided by 115, the number of days required for a revolution of Mercury, the quotient is 400, which is a round number in the vigesimal system and which was therefore denoted by a single word, by Bák in the Maya (according to Stoll) and by Huna in the Cakchiquel (according to Seler). 1,364,360, therefore, is a Huna of lunar revolutions multiplied by the number of days in the Mercury period. Later on we shall find the lunar revolution fixed at 29⅔ days.
3) 1,366,560. This is the most comprehensive number of the entire Manuscript, for it is divisible into each of the following periods:—Those of the Señores de la noche or Lords of the Cycle (9 × 151,840; this is, however, the first number of the top row), the Tonalamatls (260 × 5256), the old official years (360 × 3796), the solar years (365 × 3744), the Venus years (584 × 2340), the Mars years (780 × 1752), the Venus-solar periods (2920 × 468), the solar year-Tonalamatls (18,980 × 72), the Venus, solar, Tonalamatl periods (37,960 × 36), and the periods which are generally designated Ahau-Katuns (113,880 × 12).
We have next to consider the intervals which elapse between the three dates.
1) From 1,352,400 to 1,364,360 is 11,960 days, which period we have already found once on this page by computation.
11,960, however, is equal to 104 × 115 and 46 × 260, i.e., the Mercury revolution and the Tonalamatl combined. 11,960 is again equal to 32 × 365 + 280, and from the year 10 Kan to 3 Kan it is actually 32 years, and from the date 18 Zip to 18 Kayab it is, in fact, 280 days. The day I Ahau must be common to both dates.
2) From 1,364,360 to 1,366,560 is 2200 days, as the Manuscript expressly states. 2200, however, is equal to 8 × 260+120, and the distance from the day I Ahau to IV Ahau is in fact exactly 120 days. Further 2200=6 × 365+10; from the year 3 Kan to 9 Ix it is 6 years and from the date 18 Kayab to 8 Cumhu it is 10 days.
3) From these two statements the third follows. The distance from 1,352,400 to 1,366,560 is 14,160. This contains first the 14040, in which both the Tonalamatl and the old official year of 360 days meet, and second 120, which is again the interval between I Ahau and IV Ahau. But 14,160 is also equal to 38 × 365 + 290, and the interval between 10 Kan and 9 Ix is of course 38 years, and from 18 Zip to 8 Cumhu it is 290 days.
The numbers with which we have had to do here will again occupy our attention further on, especially the 2920 and the 37,960 on pages 46-50, the 11,960 and 115 on pages 51-58, and the 14,040 on page 73.
That these computations are not confined to the Dresden Manuscript is proved by the cross of Palenque, where we find in signs A B 16 precisely the date I Ahau 18 Zotz, a Tonalamatl before 18 Kayab, in D 1 C 2 exactly the difference 2200 and in D 3 C 4 the date IV Ahau 8 Cumhu. This is in favor of the theory that our Manuscript did not originate far from Palenque.