If two magnitudes of the same kind (a, b) have to a third magnitude (c) ratios equal to those which two other magnitudes (a′, b′) have to a third (c′), then the sum (a + b) of the first two has the same ratio to their third (c) which the sum (a′ + b′) of the other two magnitudes has to their third (c′).

Dem.—Since a : c :: a′ : c′,
we have = .
In like manner, = ;
therefore, adding, = .
Hence a + b : c :: a′ + b′ : c′.

PROP. XXV.—Theorem.
If four magnitudes of the same kind be proportionals, the sum of the greatest and least is greater than the sum of the other two.

Let a : b :: c : d; then, if a be the greatest, d will be the least [xiv. and a]. It is required to prove that a + d is greater than b + c.

Dem.—Since a : b :: c : d,
a : c :: b : d [alternando];
therefore a : a − c :: b : b − d [E].;
but a is greater than b (hyp.),
therefore a − c is greater than b − d [xiv.].
Hence a + d is greater than b + c.

Questions for Examination on Book V.

1. What is the subject-matter of this book?

2. When is one magnitude said to be a multiple of another?

3. What is a submultiple or measure?