PROP. XVII.—Theorem

1. If three right lines (A, B, C) be proportional, the rectangle (A.C) contained by the extremes is equal to the square (B2) of the mean.
2. If the rectangle contained by the extremes of three right lines be equal to the square of the mean, the three lines are proportional.

Dem.—1. Assume a line D = B; then because A : B :: B : C, we have A : B :: D : C. Therefore [xvi.] AC = BD; but BD = B2. Therefore AC = B2; that is, the rectangle contained by the extremes is equal to the square of the mean.

2. The same construction being made, since AC = B2, we have A.C = B.D; therefore A : B :: D : C; but D = B. Hence A : B :: B : C; that is, the three lines are proportionals.

This Proposition may be inferred as a Cor. to the last, which is one of the fundamental Propositions in Mathematics.

Exercises.

1. If a line CD bisect the vertical angle C of any triangle ACB, its square added to the rectangle AD.DB contained by the segments of the base is equal to the rectangle contained by the sides.

Dem.—Describe a circle about the triangle, and produce CD to meet it in E; then it is easy to see that the triangles ACD, ECB are equiangular. Hence [iv.] AC : CD :: CE : CB; therefore AC.CB = CE.CD = CD2 + CD.DE = CD2 + AD.DB [III. xxxv.].