Example.—Required the content of a spherical segment 2 feet in height, cut from a sphere of 8 feet diameter.
(3 × 8) - (2 × 2) = 20
20 × 22 × ·5236 = 41·888 cubic feet. Content required.
To find the diameter of a sphere, its solidity being given.
Divide the solidity by ·5236, and take the cube root of the quotient.
Example.—The solidity of a sphere being 113·0976 solid inches, what will be its diameter?
113·0976 ·5236 = 216, the cube root of which is 6 inches, the diameter required.
To find the weight of an iron shot, its diameter being given.
Take ⅛ of the cube of the diameter, and ⅛ of that eighth, and the sum of these two quotients will be the weight in pounds.
Or, as 64 is to 9 lb. so is the diameter cubed to its weight.
Example.—Required the weight of an iron shot whose diameter is 3·5 inches?