Fig. 103.
Represent C E by b, and E F by a, and the length of the semi-curve is
L = b[1 + ⅔(a
b)2].
Let the half span be five hundred feet, and the versed-sine or deflection eighty feet, the formula becomes
L = 500[1 + ⅔(80
500)2] = 500 × 1.0171 = 508.55 feet,
which is the half length of cables between towers.
Problem 2.
226. To find the length of the suspending rods. Calling E the horizontal distance between the vertical suspenders, we have the formula
X = Y2
b2 × a,