P s = G′2 × H
G + G′.
And, second, when the ram does not remain upon the pile,
P s =(G′
G + G′)2 × GH
Example.—A pile weighing five hundred lbs. is driven two feet, by forty blows of a 1,000 lbs. ram falling six feet. Required the weight which may be safely supported by the pile without further penetration.
The notation in the formula above is thus,
G = the weight of the pile.
G′ = the weight of the ram.
H = the fall of the ram.
s = penetration per blow.
P = the weight in lbs.