the fuel being coke; for wood, multiply the grate area (as mentioned before) by 1.4 and the grate area will be 1.4 × 9.4 = 13.16. The tube surface of course remains the same, as, when the necessary amount of heat is developed, the same surface only is enough to apply it to the water.
To obtain 779 square feet of heating surface, we see, by table 10, that it is given by
| 100 tubes | 17 | feet long and | 1¾ | inch diameter, | |
| or | 100 tubes | 16 | feet long and | 1⅞ | inch diameter, |
| or | 100 tubes | 15 | feet long and | 2 | inch diameter, |
| or | 100 tubes | 14 | feet long and | 2⅛ | inch diameter, |
| or | 100 tubes | 12½ | feet long and | 2⅜ | inch diameter, |
| or | 100 tubes | 12 | feet long and | 2½ | inch diameter, |
or by consulting the table, and having given the number and length, the number and diameter, or the length and diameter, we may easily find the third factor of the surface. Thus the length being eleven feet, and diameter two inches, 779 feet is obtained by
779
11 × 3.1416 × 167 = 135 tubes.
To obtain the diameter of barrel to contain 135 two inch tubes, we use the formula
D = √(A/B[n(d+c)2]
.7854).
We have already found d = 2 inches, n = 135, whence c will be by formula,
c = N
240 = 0.54,
and