Working independently, the same position was arrived at by Messrs. S. Loyd, E.N. Frankenstein, W.H. Thompson, and myself. So the following may be accepted as the best solution possible to this curious problem :—
| White. | Black. |
| 1. P—Q4 | 1. P—K4 |
| 2. Q—Q3 | 2. Q—R5 |
| 3. Q—KKt3 | 3. B—Kt5 ch |
| 4. Kt—Q2 | 4. P—QR4 |
| 5. P—R4 | 5. P—Q3 |
| 6. P—R3 | 6. B—K3 |
| 7. R—R3 | 7. P—KB4 |
| 8. Q—R2 | 8. P—B4 |
| 9. R—KKt3 | 9. B—Kt6 |
| 10. P—QB4 | 10. P—B5 |
| 11. P—B3 | 11. P—K5 |
| 12. P—Q5 | 12. P—K6 |
And White is stalemated.
We give a diagram of the curious position arrived at. It will be seen that not one of White's pieces may be moved.
[350.—THE FORSAKEN KING.—solution]
Play as follows:—
| White. | Black. |
| 1. P to K 4th | 1. Any move |
| 2. Q to Kt 4th | 2. Any move except on KB file (a) |
| 3. Q to Kt 7th | 3. K moves to royal row |
| 4. B to Kt 5th | 4. Any move |
| 5. Mate in two moves | |
| If 3. K other than to royal row | |
| 4. P to Q 4th | 4. Any move |
| 5. Mate in two moves | |
| (a) If 2. Any move on KB file | |
| 3. Q to Q 7th | 3. K moves to royal row |
| 4. P to Q Kt 3rd | 4. Any move |
| 5. Mate in two moves | |
| If 3. K other than to royal row | |
| 4. P to Q 4th | 4. Any move |
| 5. Mate in two moves |