Example Estimate quantities of material for 1:2 cement
mortar for topping of cellar floor 1" × 24' × 40'.
Solution—(24 × 40) = 80 cu. ft.
Cement = 80 × 0.1239 bbl. = 9.912 bbl.
Sand = 80 × 0.0344 cu. yd. = 2. 752 cu. yd.
ANALYSIS OF LABOR COST FACTORS PER CUBIC YARD
| 1 mason, 2 hours @ ....................... | |
| 2 laborers, 2 hours each @ ............... | |
| Total | $ |
| Where forms are required add | |
| 1 carpenter, 2¼ hours @ ................... | |
Cellar floor construction costs approximately the same as wall work having forms. The expense of form work in ordinary basement wall construction is offset by labor and additional cement cost of topping of cellar floor.
Brickwork.—The unit of measurement in brickwork is the 1000 bricks, ordinarily.
To determine the number of bricks in a wall, multiply each square foot of surface by 7 (sometimes 7½ is used) which is the average number of bricks per foot of wall when 4" thick. Add 5% for breakage. Deduct for openings over 2' square. For walls thicker than 4", make suitable allowance.
A mason can lay 800 to 1000 common and 300 to 400 face bricks in a day.
Bricks may be laid in lime mortar or in cement mortar.
ANALYSIS OF COST FACTORS PER 1000 BRICKS, LIME MORTAR 1:3
| Brick, 1000 @ ............................ | |
| Lime, 3 bu. @ ............................ | |
| Sand, ½ cu. yd. @ ........................ | |
| Mason, 10 hrs. @ ......................... | |
| Tender, 10 hrs. @ ........................ | |
| Total | $ |