It is the rubber game, score eighteen to nothing against the dealer. Z, the dealer, declares “no-trump.”
| ♠ J 9 8 7 5 | |||
| ♣ 5 4 | |||
| ♦ K 3 2 | |||
| ♥ K 8 7 | |||
| ♠ 6 4 2 | ![]() | ♠ K 10 | |
| ♣ A 9 2 | ♣ 10 7 3 | ||
| ♦ J 4 | ♦ A Q 10 9 7 5 | ||
| ♥ J 6 4 3 2 | ♥ 9 5 | ||
| ♠ A Q 3 | |||
| ♣ K Q J 8 6 | |||
| ♦ 8 6 | |||
| ♥ A Q 10 | |||
| TRICK | A | Y | B | Z |
| 1 | 3♥ | 7♥ | 9♥ | 10♥ |
| 2 | A♣ | 4♣ | 3♣ | K♣ |
| 3 | J♦ | 2♦ | 5♦ | 6♦ |
| 4 | 4♦ | 3♦ | 9♦ | 8♦ |
| 5 | 2♠ | K♦ | A♦ | 3♠ |
| 6 | 4♠ | 5♠ | Q♦ | Q♠ |
| 7 | 2♥ | 7♠ | 10♦ | 6♣ |
| 8 | 2♣ | 8♠ | 7♦ | 8♣ |
| 9 | J♥ | K♥ | 5♥ | Q♥ |
| 10 | 9♣ | 5♣ | 7♣ | Q♣ |
| 11 | 6♠ | 9♠ | 10♣ | J♣ |
| 12 | 4♥ | J♠ | 10♠ | A♠ |
| 13 | 6♥ | 8♥ | K♠ | A♥ |
The dealer loses the odd trick.
ILLUSTRATIVE HAND NO. 37
Trick 1.—The dealer’s first object should be to win the game. By playing the ace of spades, Z is assured of ten tricks—four in clubs, four in diamonds, one in spades, and one in hearts—whereas the play of a low spade or the queen might enable B to win the trick and establish the heart suit against the dealer; in this case, should A hold the king of clubs the game could not be won.
Trick 2.—In order to unblock the diamond suit the ace and king in Y’s hand must be led.
Trick 3.—Whether or not B covers is of minor importance, for the play of a low card does not alter the result of the hand.
Trick 5.—Z finds that his club suit is blocked by the two commanding cards in the dummy. The only possible way to make the balance of this suit is to discard the jack and ten of clubs on the two winning diamonds.
Trick 11.—Z takes out A’s king of spades, retaining the ace of hearts for re-entry.
