EXAMPLE I.
To find the time of New Moon in April 1764, N. S.
| Days | Hours | Min. | Sun’s Anom. | Moon’s Ano. | |||||
|---|---|---|---|---|---|---|---|---|---|
| s | ° | ʹ | s | ° | ʹ | ||||
| Tab. II. Mean time of New Moon in March | 2 | 8 | 57 | 8 | 2 | 23 | 10 | 13 | 32 |
| Add, for Lunation, from Tab. VI. | 29 | 12 | 44 | 0 | 29 | 6 | 0 | 25 | 49 |
| Mean New Moon and Anomaly | 31 | 21 | 41 | 0 | 1 | 29 | 11 | 9 | 21 |
| To which Time add the Moon’s Ann. Equ. Tab. VIII. | + | 0 | 22 | Equ. Moon’s Anom. | - | 20 | |||
| And it gives the Mean time corrected | 31 | 22 | 3 | Anom. cor. | 11 | 9 | 1 | ||
| From which subtract the Moon’s elliptic Equ. Tab. X. | - | 3 | 10 | Sun’s Equat. | + | 1 | 56 | ||
| Moon’s Ano. | 11 | 10 | 57 | ||||||
| And it gives the Mean time equated | 31 | 18 | 53 | h. | m. | ||||
| To which add the Sun’s Equation, Tab. XI. | + | 3 | 32 | Moon’s ann. Equ. | 0 | 22 | add | ||
| Her ellipt. Equ. | 3 | 10 | sub. | ||||||
| And it gives the true time of Conjunction | 31 | 22 | 25 | Sun’s Equation | 3 | 32 | add | ||
Which true time answers to the first of April, at 25 minutes past 10 in the forenoon: for, as the Astronomical Day begins at Noon, then 22 hours 25 min. after the Noon of March 31, is April 1, at 10 hours 25 min. in the Forenoon.
EXAMPLE II.
To find the time of Full Moon in May 1761, N. S.
| Days | Hours | Min. | Sun’s Anom. | Moon’s Ano. | |||||
|---|---|---|---|---|---|---|---|---|---|
| s | ° | ʹ | s | ° | ʹ | ||||
| Mean time of Full Moon in March | 20 | 12 | 9 | 8 | 20 | 2 | 9 | 1 | 13 |
| Add, for two Lunations | 59 | 1 | 28 | 1 | 28 | 13 | 1 | 21 | 38 |
| The several sums are | 79 | 13 | 37 | 10 | 18 | 15 | 10 | 22 | 51 |
| The days, in Tab. VII, answer to May 18 | 18 | 13 | 37 | Equ. Moon’s Anom. | - | 13 | |||
| Moon’s annual Equation add | + | 14 | Anom. cor. | 10 | 22 | 38 | |||
| Mean time corrected | 18 | 13 | 51 | Sun’s Equat. | + | 1 | 15 | ||
| Moon’s elliptic Equation subtract | - | 5 | 38 | Moon’s Ano. | 10 | 23 | 53 | ||
| Mean time equated | 18 | 8 | 13 | h. | m. | ||||
| Sun’s Equation add | + | 2 | 19 | Moon’s ann. Equ. | 0 | 14 | add | ||
| Her ellipt. Equ. | 5 | 38 | sub. | ||||||
| True time of Opposition, May | 18 | 10 | 32 | Sun’s Equation | 2 | 19 | add | ||
Namely, the 18th day, at 32 minutes past 10 at night.
The Leap-years are allowed for in the Tables, so as to give no Trouble in these Calculations.
To compute the time of New and Full Moon in a given year and month, of any particular Century, between the Christian Æra[[78]] and 18th Century.
Precept I. Find the like year of the 18th Century in [Table I.], for New Moon, or [Table III.], for Full Moon; and take out the New or Full Moon in March for that year, with the Anomalies of the Sun and Moon.
II. From [Table V], take as many compleat Centuries, as when subtracted from the above year of the 18th Century, will answer to the given year; and take out the Conjunctions and Anomalies of these Centuries.