Whence the equation for α Columbæ is

51·1 − 0·896 dφ + 0·404 dTh0 = 0 (2)

ε Canis majoris.

Watch time4h 24m 35s·8
Watch fast2 22 ·0
4 22 13 ·8
Star’s R.A.6 54 57 ·1
t 2 32 43 ·3= 38° 10′ 49″·5 E. of meridian.
φ = 24° 20′ 50″log sin 1·6151769
δ = 28° 50′ 52″·7log sin 1·6834857
1·2986626
Nat. (1) 0·1989128
φ = 24° 20′ 50″log cos 1·9595488
δ = 28° 50′ 52″·7log cos 1·9424561log cos δ1·9424
t = 38° 10′ 49″·5log cos 1·8954602 log sin t1·7911
1·7974651 1·7335
Nat. (2) 0·6272853log cos h1·9560
Nat. (1) 0·1989128 log sin A1·7775
0·4283725log cos φ1·9595
log sin h 1·6318215 1·7370
Nat. =0·546
h =25° 21′ 51″·5
log cos A1·9034
Nat. =0·801

Whence the equation for ε Canis majoris is

51·5 − 0·801 dφ + 0·546 dTh0 = 0 (3)

Collecting the equations of the three stars, we have

35·8 + 1·000 dφ − 0·011 dTh0 = 0 (1)

51·1 − 0·896 dφ + 0·404 dTh0 = 0 (2)