As a result of this operation G's total is brought above the quota, and he is declared elected.
Reg. XIV. (2).]
The next largest surplus, that of B, viz. 366, is then transferred, the operations being similar to those described in the transfer of E's surplus. Assume that there are no unexhausted papers. The new value is therefore 366 / 13 or 28. The surplus is distributed according to next preferences, as follows:
A = (7 x 28) = 196
C = (6 x 28) = 168
Value lost owing to
neglect of fractions 2
——
Total … 366
Reg XIV. (5).
G's surplus has now to be transferred, only the sub-parcel last transferred being re-examined. The details are as follows:—
Value of G's surplus 96
No. of papers in sub-parcel 10
Value of each paper therein 53
No. of unexhausted papers 10
Value of unexhausted papers 530
New value of each paper transferred = 96/10 = 9
The result of the distribution is shown on the result sheet, five papers of the value of nine each being transferred to A, and five of the same value to O.
Reg. XV. (1).