Fig. 61.

We may now proceed to an architectural example.

Let A H, [Fig. 60.], be the vertical profile of the capital of a pillar, A B the semi-diameter of its head or abacus, and F D the semi-diameter of its shaft.

Let the shaft be circular, and the abacus square, down to the level E.

Join B D, E F, and produce them to meet in G.

Therefore E C G is the semi-profile of a reversed pyramid containing the capital.

[p83]
]
Construct this pyramid, with the square of the abacus, in the required perspective, as in [Fig. 61.]; making A E equal to A E in [Fig. 60.], and A K, the side of the square, equal to twice A B in [Fig. 60.] Make E G equal to C G, and E D equal to C D. Draw D F to the vanishing-point of the diagonal D V (the figure is too small to include this vanishing-point), and F is the level of the point F in [Fig. 60.], on the side of the pyramid.

Draw F

m

, F