to cut the line of sight in N.
Fig. 14.
Then as X R′ is parallel to M N, and
a
R′ is equal to
a
X, V N must, by similar triangles, be equal to V M (equal to V T in [Fig. 13.]).
Therefore, on whichever side of V we measure the distance V T, so as to obtain either the point M, or the point N, if we measure the sight-magnitude
a