Make
a e
equal to the sight-magnitude of A E.
Now because the top and base of the pillar are in horizontal planes, the square of its top, F G, is parallel to the square of its base, B C.
Therefore the line E F is parallel to A C, and E G to A B.
Therefore E F has the same vanishing-point as A C, and E G the same vanishing-point as A B.
From
e
draw
e f