50
ends, 2 in a dent
=
25
dents
146
ends.
49
dents.
If 49 dents are required for 146 ends, the number of dents per inch in the reed will be—
50
ends, 2 in a dent
=
25
dents
146
ends.
49
dents.
If 49 dents are required for 146 ends, the number of dents per inch in the reed will be—