| Number of Teeth for Wheel to go on Lead Screw. | Lead Screw. | 12 | 18 | 24 | 30 | 36 | 42 | 48 | 54 | 60 | 66 | 72 | 78 | 84 | 90 | 96 |
| 12 | 2 | 2 | 2 | 2 | 2 | 2 | 2 | 2 | 2 | 2 | 2 | 2 | 2 | 2 | 2 | |
| 18 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | |
| 24 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | |
| 30 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | |
| 36 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | |
| 42 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | |
| 48 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | |
| 54 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | |
| 60 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | |
| Pitch of Lead Screw. | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 |
This table may be used for compound lathes by simply dividing the pitch of the lead screw by the ratio of the compounded pair of wheels. For example, for the wheels to cut 8 threads per inch, the pitch of lead screw being 4 and the compounded gears 2 to 1, as the ratio of the compounded pair is 2 to 1, we divide the pitch of lead screw by 2, which gives us 2, and we thus find the wheels in the column of pitch of lead screw 2, getting 12 and 48 as the required wheels, the 12 going on top of the lathe because it is at the top of the table, and the 48 on the lead screw because it is at the left-hand end of the table, and the lead screw gear is at the left-hand end of the lathe.
The table may be made for half threads as well as whole ones by simply advancing the left-hand column by two teeth, instead of by four, thus:—
| Teeth for Wheel on Lead Screw. | Teeth for Wheel on Stud. | |||||||||||||||||
| 12 | 16 | 20 | 24 | 28 | 32 | 36 | 40 | 44 | ||||||||||
| 12 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | 3 | |||||||||
| 14 | 3 | 1⁄2 | 3 | 1⁄2 | 3 | 1⁄2 | 3 | 1⁄2 | 3 | 1⁄2 | 3 | 1⁄2 | 3 | 1⁄2 | 3 | 1⁄2 | 3 | 1⁄2 |
| 16 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | 4 | |||||||||
| 18 | 4 | 1⁄2 | 4 | 1⁄2 | 4 | 1⁄2 | 4 | 1⁄2 | 4 | 1⁄2 | 4 | 1⁄2 | 4 | 1⁄2 | 4 | 1⁄2 | 4 | 1⁄2 |
| 20 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | 5 | |||||||||
| 22 | 5 | 1⁄2 | 5 | 1⁄2 | 5 | 1⁄2 | 5 | 1⁄2 | 5 | 1⁄2 | 5 | 1⁄2 | 5 | 1⁄2 | 5 | 1⁄2 | 5 | 1⁄2 |
| 24 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | 6 | |||||||||
| 26 | 6 | 1⁄2 | 6 | 1⁄2 | 6 | 1⁄2 | 6 | 1⁄2 | 6 | 1⁄2 | 6 | 1⁄2 | 6 | 1⁄2 | 6 | 1⁄2 | 6 | 1⁄2 |
| 28 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | 7 | |||||||||
| 30 | 7 | 1⁄2 | 7 | 1⁄2 | 7 | 1⁄2 | 7 | 1⁄2 | 7 | 1⁄2 | 7 | 1⁄2 | 7 | 1⁄2 | 7 | 1⁄2 | 7 | 1⁄2 |
| 32 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | 8 | |||||||||
| 34 | 8 | 1⁄2 | 8 | 1⁄2 | 8 | 1⁄2 | 8 | 1⁄2 | 8 | 1⁄2 | 8 | 1⁄2 | 8 | 1⁄2 | 8 | 1⁄2 | 8 | 1⁄2 |
| 36 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | 9 | |||||||||
| 38 | 9 | 1⁄2 | 9 | 1⁄2 | 9 | 1⁄2 | 9 | 1⁄2 | 9 | 1⁄2 | 9 | 1⁄2 | 9 | 1⁄2 | 9 | 1⁄2 | 9 | 1⁄2 |
| 40 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | 10 | |||||||||
| 42 | 10 | 1⁄2 | 10 | 1⁄2 | 10 | 1⁄2 | 10 | 1⁄2 | 10 | 1⁄2 | 10 | 1⁄2 | 10 | 1⁄2 | 10 | 1⁄2 | 10 | 1⁄2 |
| Pitch of Lead Screw. | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | |||||||||
For quarter threads we advance the left-hand column by one tooth, or for thirds of threads by three teeth, and so on.
If we require to find what wheels to provide for a lathe, we take the pitch of the lead screw for the numerator, and the pitch required for the denominator, and multiply them first by 2, then by 3, then by 4, and so on, continuing until the numerator or denominator is as large as it can be to give the required proportion of teeth, and not exceed the greatest number that the largest wheel can contain.
For example: A lathe has single gear, and its lead screw pitch is 8 per inch, what wheels will cut 18, 17, 16, 15, 14, or 13 threads per inch?
| Wheels. | |||||||||
| Pitch of lead screw | 8 | × 2 = | 16 | 24 | 32 | ||||
| Pitch required | 18 | 36 | 54 | 72 | |||||
| Pitch of lead screw | 8 | „ | 16 | 24 | 32 | ||||
| Pitch required | 17 | 34 | 51 | 68 | |||||
| Pitch of lead screw | 8 | „ | 16 | 24 | 32 | ||||
| Pitch required | 16 | 32 | 48 | 64 | |||||
| Pitch of lead screw | 8 | „ | 16 | 24 | 32 | ||||
| Pitch required | 15 | 30 | 45 | 60 | |||||
| Pitch of lead screw | 8 | „ | 16 | 24 | 32 | ||||
| Pitch required | 14 | 28 | 42 | 56 | |||||
| Pitch of lead screw | 8 | „ | 16 | 24 | 32 | 40 | |||
| Pitch required | 13 | 26 | 39 | 52 | 65 | ||||
If we suppose that the greatest number of teeth permissible in one wheel is not to exceed 100, then in this table we have all the combinations of wheels that can be used to cut the given pitches; and having made out such a table, comprising all the pitches to be cut, we may select therefrom the least number of wheels that will cut those pitches. The whole table being made out it will be found, of course, that the numerators of the fractions are the same in each case; that is, in this case, 16, 18, 24, 32, and so on as far as we choose to carry the multiplication of the numerator. We shall also find that the denominators diminish in a regular order: thus taking the fractions whose numerators are in each case 16, we find their denominators are, as we pass down the column, 36, 34, 32, 30, 28, and 26, respectively, thus decreasing by 2, which is the number we multiplied the left-hand column by to obtain them. Similarly in the fractions whose numerators are 24, the denominators diminish by 3, being respectively 54, 51, 48, 45, 42, and 39; hence the construction of such a table is a very simple matter so far as whole numbered threads are concerned, as no multiplication is necessary save for the first line representing the finest pitch to be cut.
For fractional threads, however, instead of using the pitch of the lead screw for the numerator, we must reduce it to terms of the fraction it is required to cut. For example, for 51⁄2 threads we proceed as follows. The pitch of the lead screw is 8, and in 8 there are 16 halves, hence we use 16 instead of 8, and as in the 51⁄2 there are 11 halves we use the fraction 16⁄11 and multiply it first by 2, then by 3, and then by 4, and so on, obtaining as follows: 16⁄11, 32⁄22, 48⁄33, 64⁄44, obtaining as before three sets of wheels either of which will cut the required pitch. In selecting from such a table the wheels to cut any required number of pitches, the set must, in order to cut a thread of the same pitch as the lead screw, contain two wheels having the same number of teeth.