EXAMPLE—A current of 42 amperes flows through three conductors in parallel of 5, 10 and 20 ohms resistance respectively. Find the current in each conductor.
SOLUTION: Joint Conductance = 1⁄5 + 1⁄10 + 1⁄20 = 7⁄20.
Supposing the current to be divided into 7 parts, 4 of these parts would flow in the first conductor 2 in the second and 1 in the third.
The whole current is 42 amperes.
4⁄7 of 42 = 24.
2⁄7 of 42 = 12.
1⁄7 of 42 = 6.
Current in first conductor = 24 amperes.
Current in second conductor = 12 amperes.
Current in first conductor = 6 amperes.
CHAPTER VII
ELECTRICAL AND MECHANICAL ENERGY
The production of electricity is simply a transformation of energy from one form into another, usually mechanical energy is changed into electrical energy and a dynamo is simply a device for effecting the transformation.