EXAMPLE.—An alternator delivers current at 800 volts pressure at a frequency of 60, to a circuit of which the resistance is 75 ohms and .25 henry.

Determine: a, the value of the current, b, angle of lag, c, apparent watts, d, power factor, e, true power.

a. Value of current

pressureE
current=
=
impedance√(R2 + (2πfL)2)
800
=
=6.7 amperes
√(752 + (2 × 3.1416 × 60 × .25)2)

b. The angle of lag

reactancefL2 × 3.1416 × 60 × .25
tan φ=
=
=
=1.25
resistanceR75
φ=angle of lag=51° 15´ (from table, page 451).

c. The apparent power

apparent power=volts × amperes=800 × 6.7=5,360 watts
=5.36 kva.

d. The power factor

power factor=cosine of the angle of lag
=cos 51° 15´=.626.