The following table gives the synchronous speed for various frequencies and different numbers of poles:
| Frequency | R.P.M. of the rotating magnetic field, when number of poles is | |||||
|---|---|---|---|---|---|---|
| 2 | 6 | 10 | 16 | 20 | 24 | |
| 25 | 1,500 | 500 | 300 | 188 | 150 | 125 |
| 60 | 3,600 | 1,200 | 720 | 450 | 360 | 300 |
| 80 | 4,800 | 1,600 | 960 | 600 | 480 | 400 |
| 100 | 6,000 | 2,000 | 1,200 | 750 | 600 | 500 |
| 120 | 7,200 | 2,400 | 1,440 | 900 | 720 | 600 |
| 125 | 7,500 | 2,500 | 1,500 | 938 | 750 | 625 |
Ques. How does the slip vary?
Ans. It varies from about 1 per cent. in a motor designed for very close regulation to 40 per cent. in one badly designed, or designed for some special purpose.
Ques. Why is the slip ordinarily so small?
Ans. Because of the very low resistance of the armature, very little pressure is required to produce currents therein, of sufficient strength to give the required torque. Hence, the necessary rate of cutting the magnetic lines to induce this pressure in the armature is reached with very little difference between the field speed and armature speed, that is, with very little slip.
Ques. How does the slip vary with the load?
Ans. The greater the load the greater the slip.
In other words, if the load increase, the motor will run slower, and the slip will increase. With the increased slip, the induced currents and the driving force will further increase. If the motor be well designed so that the field strength is constant and the lag of the armature currents is small, the driving force developed or torque will be proportional to the slip, that is the slip will increase automatically as the load is increased, so that the torque will be proportional to the load.