TABLE OF ELEVATION FOR MAXIM ·303 USING AMMUNITION GIVING 2,000 F.S.

Range.Angles of elevation on the
Maxim gun.
200yards 04·00 1
300”09·5”
400”017·0”
500”025·5”
600”035·5”
700”045·5”
800”057·5”
900”110·5”
1,000”125·5”
1,100”141·5”
1,200”157·5”
1,300”216·5”
1,400”237·5”
1,500”259·5”
1,600”322·5”
1,700”347·5”
1,800”414·5”
1,900”443·5”
2,000”514·5”
2,100”542·0”
2,200”622·0”
2,300”659·0”
2,400”740·0”
2,500”825·0”
2,600”916·0”
2,700”1018·0”
2,800”1118·0”

What is required is the angle of quadrant elevation to be put on the gun in order that the shots may strike the target at a known range. From range table obtain angle of tangent elevation; now if the target is below the guns we must subtract the angle of sight (m), if the target is above the guns we must add the angle of sight (m) to obtain correct angle of quadrant elevation.

To obtain angle of sight m

(1) When target is visible from the immediate vicinity of guns the angle may be measured by pocket clinometer or other mechanical means; or, if heights can be obtained from a contoured map, from the formula:

m = h × 1146 R

where h = difference in feet of height between guns and target; R = range in yards.

(2) When target is not visible from immediate vicinity of guns, m may be found from the following formula:

Diagram V