| Fig. 2. | Fig. 3 |
Figure 3 represents the combination,—A being Cheops, F Cephren, and D Mycerinus.
Lines DC, CA, and AD are to each other as 3, 4, and 5; and lines FB, BA, and AF are to each other as 20, 21, and 29.
The line CB is to BA, as 8 to 7; the line FH is to DH, as 96 to 55; and the line FB is to BC, as 5 to 6.
The Ratios of the first triangle multiplied by forty-five, of the second multiplied by four, and the other three sets by twelve, one, and sixteen respectively, produce the following connected lengths in natural numbers for all the lines.
| DC | 135 |
| CA | 180 |
| AD | 225 |
| ____________ | |
| FB | 80 |
| BA | 84 |
| AF | 116 |
| ____________ | |
| CB | 96 |
| BA | 84 |
| ____________ | |
| FH | 96 |
| DH | 55 |
| ____________ | |
| FB | 80 |
| BC | 96 |
Figure 4 connects another pyramid of the group—it is the one to the southward and eastward of Cheops.
In this connection, A Y Z A is a 3, 4, 5 triangle, and B Y Z O B is a square.
| Lines | YA to CA | are as | 1 to 5 |
| CY to YZ | as | 3 to 1 | |
| FO to ZO | as | 8 to 3 | |
| and | DA to AZ | as | 15 to 4. |
I may also point out on the same plan that calling the line FA radius, and the lines BA and FB sine and co-sine, then is YA equal in length to versed sine of angle AFB.