The circle is A.B.C.D, and the centre is E, the one line A.C, and the other is B.D, which two lines crosse one an other, but yet they go not by the centre, wherefore accordinge to the woordes of the theoreme, eche of theim doth cuytte the other into equall portions. For as you may easily iudge, A.C. hath one portiõ lõger and an other shorter, and so like wise B.D. Howbeit, it is not so to be vnderstãd, but one of them may be deuided into ij. euẽ parts,
but bothe to bee cutte equally in the middle, is not possible, onles both passe through the cẽtre, therfore much rather whẽ bothe go beside the centre, it can not be that eche of theym shoulde be iustely parted into ij. euen partes.
[ The L. Theoreme.]
If two circles crosse and cut one an other, then haue not they both one centre.
Example.
This theoreme seemeth of it selfe so manifest, that it neadeth nother demonstration nother declaraciõ. Yet for the plaine vnderstanding of it, I haue sette forthe a figure here, where ij. circles be drawẽ, so that one of them doth crosse the other (as you see) in the pointes B. and G, and their centres appear at the firste sighte to bee diuers. For the centre of the one is F, and the centre of the other is E, which diffre as farre asondre as the edges of the circles, where they bee most distaunte in sonder.