§ 9. A Geometrical Proposition.
The following theorem in elementary geometry will be required:—
Fig. 61.—A Useful Geometrical Proposition.
Let A B and A C be adjacent sides of a parallelogram, Fig. [61], of which A D is the diagonal, and let O be any point in its plane. Then the area O A C is the difference of the areas O A D and O A B.
Draw D Q and C P parallel to O A. Then O A D = O A Q, whence O A D – O A B = O B Q = O A P = O A C.
§ 10. Relation Between the Change of Moment of Momentum and the Force Acting on the Particle.
Fig. 62.—Acceleration of Moment of Momentum equals Moment of Force.
Let A1 and A2, Fig. [62], be two adjacent points on the path of the particle, and let A1 Q and A2 R be the tangents at those points. Let S Q represent the velocity of the particle at A1, and SR the velocity of the particle at A2. Then Q R represents both in magnitude and direction the change in velocity due to the force F, which we suppose constant both in magnitude and direction, while the particle moves from A1 to A2 in the small time t; we have also Q R = F t ÷ m.