The graphic symbol for CH3OH is—-

H
|
H-C-OH;
|
H

for C2H5OH it is—

H H
| |
H-C-C-OH.
| |
H H

Write it for the next two.

300. Ethers.—Another interesting class of compounds are the oxides of the marsh-gas series. In this series, O replaces H. CH3H becomes (CH3)2O, and C2H5H becomes (C2H5)2O. Why is a double radical taken? These oxides are ethers, common or sulphuric ether being (C2H5)2O. Complete this table, by substituting O in place of H, in the table on page 176.

1. (CH3)2O, methyl oxide, or methyl ether. 2. (C2H5)2O, ethyl oxide, or ethyl ether. 3. ? ? ? 4. ? ? ? 5, etc. ? ? ?

Graphically represented the first two are:—

H H H H H H
| | | | | |
(1) H-C-O-C-H. (2) H-C-C-O-C-C-H.
| | | | | |
H H H H H H

301. Substitutions.—A large number of other substitutions can be made in each symbol, thus giving rise to as many different compounds.