Let R = distance of CG2 below CP2 = ag.
Let S = distance of thrust-line below CP2 = ad.
If now the aerodrome under the action of the propellers be supposed to turn about the CP2 (or, a) through an angle α, so that g takes the position g′, we [p049] obtain by the decomposition of the force of gravity an element g′k = W sin α which acts in a direction parallel to the thrust-line.
If we again neglect the horizontal hull resistance, equilibrium will be obtained when
kg′ × ag′ = T × ad′
or
WR sin α = TS
∴ α = sin−1TSWR
Fig. 5. Diagram showing relation under certain conditions of thrust, C. P. and C. G.