Attached Therm.60°.6;Air-ditto, 60°.2:
Above: Barom.- -Inches 29, .5218:
Attached Therm.56°.6;Air-ditto, 57°.
Subtract the colder——from the warmer,
and there remains4°of Heat to be added

to the colder Barometer; to give it an equal Temperature: which is to be done by the 1st Table, thus:

Section, 356.

To find the Expansion with 4° of Heat, on the colder Barometer; (which, as before, is the upper Barometer) standing at Inches 29, .5218 Tenths.

First, with 4° on 29 Inches =

 .0117:
2d, with 4° on .5218 Tenths above 29 Inches:
In order to obtain which, begin

with 4° on 29 =

 .0117

then with 4° on 30 =

 .0121

Subtract for the Expansion with

 ——

4° on 1 Inch above 29, and there remains

 .0004.

Section 362.

Then for the Expansion with 4° on .1 Tenth of an Inch above 29 Inches; add a Cypher and decimal Point,

Section 363.

viz.

.00004

 :
Then for the Expansion on

.5128,

 multiply
the two last Terms, and divide

———
the Product by the first Term
.1: the Answer is

.0002

 |0872
Add the Expansion with 4° on
29 Inches, just found,

.0117
to the Inches of the colder
Barometer, viz.

29.5218

———
Answer; Inches

29.5337

 Tenths of
the colder Barometer, are now expanded equally
with the warmer: (rejecting the Decimals as in
Section 395.)
Place the Barometers, thus:
Upper Barometer,

29.5337
Lower Barometer,

30.0168

End of the first Stage.