| As Sound travels | 1142 | Feet in a |
| Second, it must have moved in | 30 | Seconds |
| ——— | ||
| Feet in a Yard | 3)34260 | = Feet |
| Yards in a Mile | 1760)11420 | (6 Miles |
| 10560 | ||
| —— | ||
| Yards in a Quarter of a Mile | 440)860 | (1 Quarter |
| 440 | ||
| —— | ||
| Answer 6 Miles, 1 Quarter, and | 420 | Yards. |
[22] Equal to 2085 Yards; or 1 Mile, 325 Yards.
[23] Long’s Astronomy. Pages 227, 229.
[24] Also called the Horsham Stone, from a Place so named, in Surrey, where great Quantities are found.
PROBLEM.
To find the Length of the Shadow from a Person of middle Stature, (five Feet and a half High) viz. at XII o’Clock, on the 8th Day of September, 1785, at Chester, whose North Latitude is 53° 12′; (and 3° 11′ West Longitude from London.)
FIRST,
| To find the Sun’s Altitude at XII. | ||
From | 90°. 00′′ | Subtract |
The Latitude | 53. 12 | |
——— | ||
The Remain. | 36. 48 | is the Complement of Latitude, to which add (from the Tables) |
Sun’s N. Decl. | 5. 29 | |
——— | ||
The Remain. | 42. 17 | is the Sun’s Altitude (viz. at XII.) |