To find the arc AR.

By combining the two proportions already given, we have by logarithms:

M. R. V. minor=3256 Log.3.512683
M. S. D. of moon=940″"2.973128
P. S. D. of earth=3950 A. C.6.403403
Radius10.000000
T. S. D. of moon885″.5 A. C.7.052811
Log. Cosine arc AR=28° 57′ 3″9.942025

As the only variable quantity in the above formula is the “True” semi-diameter of the moon at the time, we may add the Constant logarithm 2.889214 to the arithmetical complement of the logarithm of the true semi-diameter, and we have in two lines the log. cosine of the arc AR.

We must now find the arc RK equal at a maximum to 2° 45′. The true longitude of the moon’s node being 79° 32′, and the moon’s longitude, per Nautical Almanac, being 58° 30′, the distance from the node is 21° 2′, therefore, the correction is

To find the correction for displacement.

True longitude of sun at date100°30′
" of moon"58°30′
Moon’s distance from quadrature48°0′