Mr. Frazier. I was unable to reach a conclusion as to whether or not it had been fired from this rifle. The conclusion went slightly further than that, in that we determined that the general rifling characteristics of the rifle 139 are of the same type as those found on the bullet, Exhibit 573, and, further, on this basis, that the bullet could have been fired from the rifle on the basis of its land and groove impressions. And, second, that all of the remaining physical characteristics of this bullet, 573, are the same as Western 6.5mm. Mannlicher-Carcano bullets of the type normally loaded in ammunition made for this rifle, 139. However, the mutilation of the nose of the bullet has eliminated the length characteristics, and it cannot be definitely stated that Exhibit 573 is in fact a Western Cartridge Co. product, but all of the remaining characteristics of base shape, distance from the base to the cannelure, the width of the cannelure, and the overall appearance, coloration, and so forth, are similar to Western ammunition.

Mr. Eisenberg. Is this a jacketed bullet?

Mr. Frazier. Yes, it is a copper-alloy jacketed bullet having a lead core.

Mr. Eisenberg. Can you think of any reason why someone might have called this a steel-jacketed bullet?

Mr. Frazier. No, sir; except that some individuals commonly refer to rifle bullets as steel-jacketed bullets, when they actually in fact just have a copper-alloy jacket.

Mr. Eisenberg. Can you describe the general rifling characteristics which you referred to?

Mr. Frazier. Yes. They consist of impressions from four lands and grooves. The bullet is mutilated on a portion of its surface. However, it can be determined that there were four land impressions and four groove impressions originally on this bullet.

The width of the land impression is 7/100ths of an inch, that is 0.07 inch—whereas the width of the groove impression is 0.13 inch, or 13/100ths of an inch.

The bullet is flattened so that it was not possible to measure its diameter. However, by adding the land width to the groove width, and multiplying by the number of lands and grooves, you can determine the circumference of the bullet and mathematically determine its diameter, which in this case corresponds to 6.5 mm. ammunition, or approximately .267 inch.

Mr. Eisenberg. What was the direction of the twist?