From this deduct the area of y z u, which is the portion covered by the intersecting gable roof. The true length of t u along the slope is t u′, measuring 12 feet; hence, the area of y z u is
| 14 × 12 | = 84 square feet. |
| 2 |
The net area of a p q c is therefore 228 - 84 = 144 square feet; b c q w being equal to a p q c, its area is the same, making the area of both sides 288 square feet.
The area of k n m l is
| m n + l k | × m l′, |
| 2 |
the slope length of m l. Substituting dimensions, the area is
| 11 + 16 | × 8.5 = 114.8 square feet. |
| 2 |
As k l x w is equal to k n m l, the area of both is 229.6 square feet.
Adding the partial areas thus obtained, the sum is 155.3 + 402.8 + 107.2 + 288 + 229.6 = 1,182.9 square feet, or approximately 11.9 squares.