To find the day of the week for any given date.

1. Take the last two figures of the year, add one-fourth of them (neglecting remainder). Thus: 1949 = 49 + 12 = 61.

2. Add for the month, if for January or October, 1; May, 2; August, 3; February, March, or November, 4; June, 5; September or December, 6; April or July, 0; if leap year (that is, if it be divisible by 4 without remainder) January 0; February 3.

3. Add day of month.

Divide the sum of these three by 7, and remainder gives the number of the day of the week.

Thus:—What day of the week is 15th July, 1908?

1. 8 + 2=10
2. July=0
3. 15th=15
25=7 × 3 + 4

4th day of the week = Wednesday.

What day of the week was December 25th, 1905?

1. 5 + 1=6
2. Dec.=6
3. 25th=25
37=7 × 5 + 2